F stops between f numbers
For the number of f stops between two f numbers (e.g. f11.8 and 7.4). Given f_1 and f_2:
i=log(f_1/f_2) / log(sqrt(2))
where i is the difference in f stops for exposure.
So for f11.8 and 7.4:
i=log(11.8/7.4)/(log(sqrt(2)) = 1.35 f stops.
This is 2^i times the amount of light (in this example 2^1.35=2.55 times the amount of light at f7.4 than at 11.8).
i=log(f_1/f_2) / log(sqrt(2))
where i is the difference in f stops for exposure.
So for f11.8 and 7.4:
i=log(11.8/7.4)/(log(sqrt(2)) = 1.35 f stops.
This is 2^i times the amount of light (in this example 2^1.35=2.55 times the amount of light at f7.4 than at 11.8).